1/x-5x-3/x^2-4x=7x-9/x^2-4x

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Solution for 1/x-5x-3/x^2-4x=7x-9/x^2-4x equation: 



1/x-5x-3/x^2-4x=7x-9/x^2-4x

We move all terms to the left:

1/x-5x-3/x^2-4x-(7x-9/x^2-4x)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R





Domain of the equation: x^2-4x)!=0

x∈R



We add all the numbers together, and all the variables

-9x+1/x-3/x^2-(7x-9/x^2-4x)=0

We get rid of parentheses

-9x+1/x-3/x^2-7x+9/x^2+4x=0

We calculate fractions

We do not support expression: x^3

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